20. Valid Parentheses¶
Description¶
Given a string s containing just the characters '('
, ')'
, '{'
, '}'
, '['
and ']'
, determine if the input string is valid.
An input string is valid if:
- Open brackets must be closed by the same type of brackets.
- Open brackets must be closed in the correct order.
- Every close bracket has a corresponding open bracket of the same type.
Example 1:
Input: s = "()"
Output: true
Example 2:
Input: s = "()[]{}"
Output: true
Example 3:
Input: s = "(]"
Output: false
Example 4:
Input: s = "([])"
Output: true
Constraints:
- 1 <= s.length <= \(10^{4}\)
- s consists of parentheses only '()[]{}'.
Solutions¶
I Stack¶
Complexity:
- Time complexity: \(O(n)\), where \(n\) is the length of the input string.
- Space complexity: \(O(n)\), where \(n\) is the length of the input string.
func isValid(s string) bool {
stack := make([]rune, 0)
m := map[rune]rune{
')': '(',
']': '[',
'}': '{',
}
for _, c := range s {
switch c {
case '(', '[', '{':
stack = append(stack, c)
case ')', ']', '}':
if len(stack) == 0 || stack[len(stack)-1] != m[c] {
return false
}
stack = stack[:len(stack)-1]
}
}
return len(stack) == 0
}